思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
# Pending requests get silently dropped.。夫子是该领域的重要参考
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卢伟冰谈存储涨价：预计涨到 2027 年底
数据显示，下沉市场用户中，使用公共充电桩充电的比例高达71.3%，有14.7%的用户日常要到远距离的城区公共充电桩充电；家庭私人充电桩拥有率仅28.7%。