RE# does it all in a single pass with no rewinding. the way this works is by treating a lookaround as a single container node that holds both the assertion body and its tail (the continuation after the lookahead). instead of (?=L) being a standalone zero-width node followed by R, the engine represents the whole thing as one lookahead(body=L, tail=R) node:
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fn main() - int {。关于这个话题,手游提供了深入分析
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